Answer:
If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops, then the specific heats of both objects will be equal.
Explanation:
If the temperature of the colder object rises by the same amount as the temperature of the hotter object drops when the two objects of same mass are brought into contact, then their specific heat capacity is equal.
We can prove this by the equation of heat for the two bodies:
According to given condition,
[tex]\Delta T_1=\Delta T_2[/tex]
[tex]\frac{Q_1}{m_1.c_1} = \frac{Q_2}{m_2.c_2}[/tex]
when there is no heat loss from the system of two bodies then [tex]Q_1=Q_2[/tex]
[tex]\frac{1}{m.c_1} =\frac{1}{m.c_2}[/tex]
[tex]\Rightarrow c_1=c_2[/tex]
The temperature of the colder object will rise twice as much as the temperature of the hotter object only in two cases:
OR