The the value of f(n)=[tex]\frac{28}{3}[/tex]
Step-by-step explanation:
The Arithemetic sequence is given as a,a+d,a+2d......a(n-1)d
and f(n)=a(n-1)d
The given sequence is 1/3,4/3,7/3...
By comapring with Arithemetic sequence,
we get a=1/3
a+d=4/3
1/3 + d = 4/3
d=1
To find value of f(10):
take n=10
f(n)=[tex]\frac{1}{3} +(10-1)1[/tex]
f(n)=[tex]\frac{1}{3} +(9)1[/tex]
f(n)=[tex]\frac{1+27}{3}[/tex]
f(n)=[tex]\frac{28}{3}[/tex]
