Hello!
Given the quadratic equation in standard form
∙xax2+bx+c=0x;a≠0
We can solve for x using the quadratic formula
∙xx=−b±√b2−4ac2a
x2+4x+1=0 is in standard form
with a=1,b=4 and c=1
⇒x=−4±√16−42=−4±√122
x=−4±2√32=−2±√3←exact values
Hope this helps!
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