A person exerts a horizontal force of 42 N on the end of a door 96 cm wide. What is the magnitude of the torque if the force is exerted (a) perpendicular to the door and (b) at a 60.0° angle to the face of the door?

Respuesta :

Answer:

(a) [tex]\tau=40.32N\cdot m[/tex]

(b) [tex]\tau=34.92N\cdot m[/tex]

Explanation:

Torque is the ability of a force to change the state of rotation of the body around an axis that passes through a given point. Therefore, it is defined as:

[tex]\tau=Frsin\theta[/tex]

(a) In this case the angle between the force and the face of the door is [tex]90^\circ[/tex]:

[tex]\tau=(42N)(96*10^{-2}m)sin90^\circ\\\tau=40.32N\cdot m[/tex]

(b)

[tex]\tau=(42N)(96*10^{-2}m)sin60^\circ\\\tau=34.92N\cdot m[/tex]