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Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.
Solution A: [ OH − ] = 3.33 × 10 − 7 M
Solution A: [ H 3 O + ] = M
Solution B: [ H 3 O + ] = 9.33 × 10 − 9 M
Solution B: [ OH − ] = M
Solution C: [ H 3 O + ] = 5.65 × 10 − 4 M
Solution C: [ OH − ] = M

Respuesta :

Answer: Solution A : [tex][H_3O^+]=0.300\times 10^{-7}M[/tex]

Solution B : [tex][OH^-]=0.107\times 10^{-5}M[/tex]

Solution C : [tex][OH^-]=0.177\times 10^{-10}M[/tex]

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

[tex]pH=-\log[H_3O^+][/tex]

[tex]pOH=-log[OH^-}[/tex]

[tex]pH+pOH=14[/tex]

[tex][H_3O^+][OH^-]=10^{-14}[/tex]

a. Solution A: [tex][OH^-]=3.33\times 10^{-7}M[/tex]

[tex][H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M[/tex]

b. Solution B : [tex][H_3O^+]=9.33\times 10^{-9}M[/tex]

[tex][OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M[/tex]

c. Solution C : [tex][H_3O^+]=5.65\times 10^{-4}M[/tex]

[tex][OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M[/tex]

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