contestada

A 500 kg car traveling at 20 m/s, brakes and skids to a stop. If μk = 0.7 between the tires and the road, the acceleration of the car during the skid is:


a. -0.7 m/s2


b. -7.0 m/s2


c. -2.0 m/s2


d. -0.2 m/s2

Respuesta :

skyluke89

The acceleration of the car is [tex]-7.0 m/s^2[/tex]

Explanation:

The only force acting on the car is the force of friction, which acts backward. The force of friction is given by

[tex]F_f = -\mu_k mg[/tex]

where

[tex]\mu_k =0.7[/tex] is the coefficient of kinetic friction

m = 500 kg is the mass of the car

[tex]g=10 m/s^2[/tex] is the acceleration of gravity

The acceleration of the car is given by Newton's second law:

[tex]a=\frac{F}{m}[/tex]

where

F is the net force on the car

Since the only force acting on the car is the force of friction, [tex]F=F_f[/tex], so the acceleration is

[tex]a=\frac{-\mu mg}{m}=-\mu g=-(0.7)(10)=-7.0 m/s^2[/tex]

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