According to the question :
Let; jeans=j
sweatshirts=s
⇒5 pair of jeans i.e 10 jeans and 2 sweatshirts costs=$207
10j+2S=$207 (i)
⇒ 3 pair of jeans i.e 6 jeans and 4 sweatshirts costs=$169
6J+4S=$167 (ii)
MULTIPLY equation (1) by 2
10j+2S=$207 (i)×2
⇒20j+4s=$414 (iii)
By applying a Simultaneous equation
On adding equation (ii) and (iii) we get
j=$17.6
s= $15.5
∴cost of 1 sweatshirt s= $15.5
a set of two or more equations, each containing two or more variables whose values can simultaneously satisfy both or all the equations in the set, the number of variables being equal to or less than the number of equations in the set.
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