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Answer:

[tex]\displaystyle 1\frac{1}{3}[/tex]

Step-by-step explanation:

[3, 1] and [0, −3]

[tex]\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{3 + 1}{0 + 3} = \frac{4}{3} = 1\frac{1}{3}[/tex]

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Answer : The slope of line is, [tex]\frac{4}{3}[/tex]

Step-by-step explanation :

The general form for the formation of a linear equation is:

[tex](y-y_1)=m\times (x-x_1)[/tex] .............(1)

where,

x and y are the coordinates of x-axis and y-axis respectively.

m is slope of line.

Now we have to calculate the slope of line.

Formula used :

[tex]m=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]

Here,

[tex](x_1,y_1)=(3,1)[/tex] and [tex](x_2,y_2)=(0,-3)[/tex]

[tex]m=\frac{(-3-1)}{(0-3)}[/tex]

[tex]m=\frac{-4}{-3}[/tex]

[tex]m=\frac{4}{3}[/tex]

Therefore, the slope of line is, [tex]\frac{4}{3}[/tex]

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