The new centripetal force will be 1/3 of the original force.
Explanation:
The centripetal force experienced by an object in uniform circular motion is given by
[tex]F=m\frac{v^2}{r}[/tex]
where
m is the mass of the object
v is its speed
r is the radius of the circle
In this problem, the initial force on the mass in circular motion is [tex]F[/tex]. Later, the radius of the circle is tripled:
[tex]r'=3r[/tex]
Assuming that the speed remains the same, the new centripetal force will be:
[tex]F'=m\frac{v^2}{r'}=m\frac{v^2}{3r}=\frac{1}{3}(m\frac{v^2}{r})=\frac{F}{3}[/tex]
So, the new centripetal force will be 1/3 of the original force.
Learn more about centripetal force:
brainly.com/question/2562955
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