Answer:
If this was what I think you meant, it would be x = -2 & 3
Step-by-step explanation:
0 = (x^2 - x - 6)
0 = (x+2)(x-3)
x= -2, 3
The solutions to the equation are x=-2 and x=3.
The quadratic function can be represented by a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a[tex]\neq[/tex]0) and the degree of the function must be equal to 2.
In math, factoring or factorization is used to write an algebraic expression in factors.
The given equation is x²-x-6=0.
You can rewrite this equation with two factors, as shown below:
x²-x-6= (x+2)* (x-3)
x²-x-6= x²-3x+2x-6
x²-x-6= x²-x-6
Therefore, you can find the roots from (x+2) and (x-3).
x+2=0 x-3=0
x=-2 x=3
So, the solutions to the equation are x=-2 and x=3.
Learn more about the factoring here:
https://brainly.com/question/11579257
