Answer:
(c) 4
Explanation:
Let us represent number with Ni
the first number is 20
first stage program execution: is N0 (20) greater than 0
20 > 0
hence
N1 = 20/2 = 10
count = 1
second stage program execution: is N1 (10) greater than 0
10 > 0
hence
N2 = 10/2 = 5
count = 2
third stage program execution: is N2 (5) greater than 0
5 > 0
hence
N3 = 5/2 = 2.5
count = 3
first stage program execution: is N3 (2.5) greater than 0
2.5 > 0
hence
N3 = 2.5/2 = 1.25
count = 4
the program however terminates here as number is supposed to be an integer, not a float. Hence for N3 = 2.5 being a float, not an integer, there is a count but the program ends.
