Respuesta :
Answer:
y = [tex]\frac{3}{5}[/tex] x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 5, - 1) and (x₂, y₂ ) = (5, 5)
m = [tex]\frac{5+1}{5+5}[/tex] = [tex]\frac{6}{10}[/tex] = [tex]\frac{3}{5}[/tex], thus
y = [tex]\frac{3}{5}[/tex] x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (5, 5), then
5 = 3 + c ⇒ c = 5 - 3 = 2
y = [tex]\frac{3}{5}[/tex] x + 2 ← equation of line
The equation of line that goes through the points (-5,-1) and (5.5) is y=3/5x+2.
What is equation of line?
The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term.
It is an equation of degree one, with variables x and y. The values of x and y represent the coordinates of the point on the line represented in the coordinate plane.
we have,
[tex]x_1=-5\;, x_2=5\;, y_1=-1\;, y_2=5[/tex]
Now, equation of line
(y-y1)= (y2-y1)/(x2-x1)* (x-x1)
y-(-1)= (5-(-1))/(5-(-5))*(x-(-5))
y+1= 6/10 *(x+5)
y+1= 3/5(x+5)
5y+5=3x+15
5y=3x+10
y=3/5x+2
Hence, the equation of line is y=3/5x+2
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