Answer:
Mass of P4O6=103.4
P4O10=133.48
Explanation:
Balanced reaction is:
8P +8[tex]O_{2}[/tex] ⇒[tex]P_{4} O_{6}[/tex] +[tex]P_{4} O_{10}[/tex]
Both reactant completely vanishes as equivalent of bot are equal.
Moles of P=[tex]\frac{117.9}{31}[/tex] =3.80
Moles of [tex]O_{2}[/tex] =[tex]\frac{117.9}{31}[/tex] =3.80
No. of moles of formed product are equal and is [tex]\frac{1}{8}[/tex]th of mole of any of reactant.
Thus weight of [tex]P_{4} O_{6}[/tex] =[tex]\frac{3.80}{8}[/tex]×220 ≈103.41
weight of [tex]P_{4} O_{10}[/tex] =[tex]\frac{3.80}{8}[/tex]×284 ≈133.48
