Respuesta :
Answer:
Two parabolas one facing down with a vertex at 0, 3 and one facing up with a vertex at 0, negative 3
Step-by-step explanation:
we have
[tex]\frac{3}{4}x^{2}-3=-\frac{3}{4}x^{2}+3[/tex]
This equation is equivalent to solve for x the following system of equations
[tex]y=\frac{3}{4}x^{2}-3[/tex] ----> equation A
This is the equation of a vertical parabola open up with vertex at (0,-3)
[tex]y=-\frac{3}{4}x^{2}+3[/tex] ----> equation B
This is the equation of a vertical parabola open down with vertex at (0,3)
Solve the system of equations by graphing
The solutions are the x-coordinates of the intersection point both graphs
using a graphing tool
The solution is x=-2, x=2
see the attached figure
