Answer:
see the explanation
Step-by-step explanation:
The correct question is
Use the discriminant to determine how many solutions are possible for the following equation (show work).
5x^2-3x+4=0
we know that
The discriminant for a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]D=b^2-4ac[/tex]
If D=0 then the equation has only one real solution
If D>0 then the equation has two real solutions
If D<0 then the equation has no real solutions (two complex solutions)
in this problem we have
[tex]5x^{2} -3x+4=0[/tex]
so
[tex]a=5\\b=-3\\c=4[/tex]
substitute
[tex]D=-3^2-4(5)(4)[/tex]
[tex]D=-71[/tex]
so
The equation has no real solutions, The equation has two complex solutions
therefore
I know there are___No____
real solutions to the equation in problem 4 because ___the discriminant is negative___
