Respuesta :
The question is incomplete, here is the complete question:
You need to prepare 250. mL of a 0.300 M aqueous solution of sucrose, [tex]C_{12}H_{22}O_{11}[/tex] (aq), which is used frequently in biological experiments. Based on your answer above, measure out the amount of solid sucrose in the solution.
Answer: The mass of solid sucrose present in the solution is 25.7 grams.
Explanation:
To calculate the mass of sucrose, we use the equation used to calculate the molarity of solution:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
Molarity of solution = 0.300 M
Molar mass of sucrose = 342.3 g/mol
Volume of solution = 250. mL
Putting values in above equation, we get:
[tex]0.300mol/L=\frac{\text{Mass of sucrose}\times 1000}{342.3g/mol\times 250.}\\\\\text{Mass of sucrose}=\frac{0.300\times 342.3\times 250.}{1000}=25.7g[/tex]
Hence, the mass of solid sucrose present in the solution is 25.7 grams.
