Answer : The actual yield of iron in moles is 0.25 moles.
Solution : Given,
Mass of Fe = 14.0 g
Molar mass of Fe = 56 g/mole
Now we have to calculate the moles of [tex]Fe[/tex].
Formula used :
[tex]\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}[/tex]
Now put all the given values in this expression, we get:
[tex]\text{ Moles of }Fe=\frac{14.0g}{56g/mole}=0.25moles[/tex]
Therefore, the actual yield of iron in moles is 0.25 moles.
