The following questions refer to the reaction 2A2 + B2 -> 2C. The following mechanism has been proposed: step 1 (very slow): A2 + B2 -> R + C step 2 (fast): A2 + R -> C Which step is rate determining?

Respuesta :

Answer: The first step of the mechanism is the rate determining step.

Explanation:

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

[tex]2A_2+B_2\rightarrow 2C[/tex]

The intermediate reaction of the mechanism follows:

Step 1:  [tex]A_2+B_2\rightleftharpoons R+C;\text{ (very slow)}[/tex]

Step 2:  [tex]A_2+R\rightarrow C;\text{ (fast)}[/tex]

As, step 1 is the slow step, it will determine the rate of the reaction and is the rate determining step.

Rate law for the reaction will be:

[tex]\text{Rate}=k[A_2][B_2][/tex]

Hence, the first step of the mechanism is the rate determining step.