Respuesta :
Answer:
I = 8.31 A
Explanation:
given,
Thermal Energy = 1 kW
Emf amplitude = 170 V
AC oscillation = 60 Hz
[tex]E_{rms} = \dfrac{E_{max}}{\sqrt{2}}[/tex]
[tex]E_{rms} = \dfrac{170}{\sqrt{2}}[/tex]
[tex]E_{rms} =120.21\ V[/tex]
Rms current is calculated as
P = VI
[tex]I =\dfrac{P}{V}[/tex]
[tex]I =\dfrac{1000}{120.21}[/tex]
I = 8.31 A
the root-mean-square current through the heating element is equal to I = 8.31 A
The root-mean-square current through the heating element will be
I = 8.31 A
What is root-mean-square current?
It is given that,
Thermal Energy =E= 1 kW
Emf amplitude=[tex]E_{max}[/tex]= 170 V
AC oscillation=f= 60 Hz
[tex]E_{rms} = \dfrac{E_{max} }{\sqrt{2} }[/tex]
[tex]E_{rms} =\dfrac{170}{\sqrt{2} }[/tex]
[tex]E_{rms} = 120.21V[/tex]
So the RMS current will be calculated by
[tex]P=VI[/tex]
[tex]I=\dfrac{P}{E_{rms} }[/tex]
[tex]I=\dfrac{1000}{120.21}=8.31A[/tex]
[tex]I=8.31A[/tex]
Thus the root-mean-square current through the heating element will be
I = 8.31 A
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