Question:
The sum of 5 consecutive integers is 110 . What is the fourth number in this sequence
Answer:
The fourth number in this sequence is 23
Step-by-step explanation:
Explanation:
Consecutive numbers are numbers that come one after another with no numerical gaps. Like these:
4, 5 , 6 , 7 , 8 or these 17 , 18, 19 , 20 , 21
We need to find 5 consecutive integers that add up to 110.
Let's call the first integer in the series
N for number . The next integer will be
N + 1 since it is 1 greater than N .
The next integers will be N+ 2 , N + 3 and N + 4 since they are 2, 3 and 4 greater than N respectively.
N + ( N + 1 ) + ( N + 2 )+( N + 3 ) + ( N + 4 ) = 110
Now remove parentheses and add like terms:
N + N + 1 + N + 2 + N + 3 + N + 4 = 110
5N + 10 = 110
Now finish simplifying:
5 N + 10= 110
5 N = 100
[tex]N = \frac{100}{5}[/tex]
N = 20
Since N = 20
our 5 consecutive numbers are:
20 , 21 , 22 , 23 , 24
