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A car moves along a straight road in such a way that its velocity (in feet per second) at any time t (in seconds) is given by v(t) = 3t 9 − t2 (0 ≤ t ≤ 3).

Respuesta :

akiran007

Answer:

velocity varies between 25,50 and 75 (feet per second)

Step-by-step explanation:

as t varies between 0 and 3

putting t=0

v(0)= 3(0)9- 0(2)

v(0)= 0

now putting t= 1 in the given equation

v(1)= 3(1)9-(1)2

v(1)= 27-2

V(1)=25

now putting t= 2 in the given equation

V(2)= 3(2)9-(2)2

V(2)= 54-4

V(2)=50

now putting t= 3 in the given equation

V(3)= 3(3)9-(3)2

V(3)= 81-6

V(3)=75

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