Answer:
In a dihybrid cross, in which both parents are heterozygous for both traits, the probability that the offspring will exhibit both of the dominant phenotypes is 0.75
Explanation:
From the above analogy, we could say;
heterozygous (Bb) X (Bb)= this will give us BB, Bb, Bb, and bb
BB= homozygous dominant,
Bb= Heterozygous dominant
bb= Homozygous recessive
From the above result, 75% of the dominant phenotypes is produced while 25% of the recessive phenotypes is produced
