contestada

The steps in writing f(x)=18x+3x2 in vertex form are shown, but a value is missing in the last step.

Write the function in standard form.
Factor a out of the first two terms. f(x)=3(x2+6x)

Form a perfect square trinomial. (six-halves) squared

f(x)=3(x2+6x+9)−3(9)

Write the trinomial as a binomial squared. f(x)=3(x+___)2−27

Respuesta :

calculista

Answer:

[tex]f(x)=3(x+3)^{2}-27[/tex]

Step-by-step explanation:

we have

[tex]f(x)=18x+3x^{2}[/tex]

Write the function in standard form

[tex]f(x)=3x^{2}+18x[/tex]

Factor 3 out of the first two terms

[tex]f(x)=3(x^{2}+6x)[/tex]

Form a perfect square trinomial. (six-halves) squared

[tex]f(x)=3(x^{2}+6x+9)-3(9)[/tex]

[tex]f(x)=3(x^{2}+6x+9)-27[/tex]

Write the trinomial as a binomial squared

[tex]f(x)=3(x+3)^{2}-27[/tex]

therefore

The vertex is the point (-3,-27)

rgrazer03

Answer:

3

Step-by-step explanation:

f(x)=3(x+3)2−27

the missing value is 3

Otras preguntas