Answer:
Concentration of solution B is [tex]7.10\times 10^{-6}M[/tex]
Explanation:
Solution A: Total volume of solution A = (9.00+1.00) mL = 10.00 mL
According to law of dilution, [tex]C_{1}V_{1}=C_{2}V_{2}[/tex]
where [tex]C_{1}[/tex] and [tex]C_{2}[/tex] are initial and final concentration respectively. [tex]V_{1}[/tex] and [tex]V_{2}[/tex] are initial and final volume respectively.
Here [tex]C_{1}[/tex] = [tex]3.55\times 10^{-4}M[/tex], [tex]V_{1}[/tex] = 1.00 mL, [tex]V_{2}[/tex] = 10.00 mL
So, [tex]C_{2}=\frac{C_{1}V_{1}}{V_{2}}[/tex] = [tex]\frac{3.55\times 10^{-4}M\times 1.00mL}{10.00mL}=3.55\times 10^{-5}M[/tex]
So, concentration of solution A = [tex]3.55\times 10^{-5}M[/tex]
Solution B: Total volume of solution B = (2.00+8.00) mL = 10.00 mL
Similarly as above, [tex]C_{2}=\frac{C_{1}V_{1}}{V_{2}}[/tex] = [tex]\frac{3.55\times 10^{-5}M\times 2.00mL}{10.00mL}=7.10\times 10^{-6}M[/tex]
So, concentration of solution B = [tex]7.10\times 10^{-6}M[/tex]
