The speed of the object increases
Explanation:
We can answer this question by applying the work-energy theorem, which states that the work done on an object is equal to the change in kinetic energy of the object. Mathematically:
[tex]W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]
where
W is the work done on the object
[tex]K_f, K_i[/tex] are the final and initial kinetic energy of the object, respectively
m is the mass of the object
v is its final speed
u is its initial speed
In this case, the force does a positive amount of work on the object, so
[tex]W>0[/tex]
This also implies that
[tex]K_f > K_i[/tex]
And so
[tex]\frac{1}{2}mv^2 > \frac{1}{2}mu^2[/tex]
And therefore
[tex]v>u[/tex]
which means that the speed of the object increases.
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
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