Answer:
c) 75, 2
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample mean, with a large sample size, can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\frac{\sigma}{\sqrt{n}}[/tex].
In this problem, we have that:
Records show that the weights of boxes that it carries have a mean of 75 lb and a standard deviation of 16 lb. This means that [tex]\mu = 75, \sigma = 16[/tex].
For sample size of 64, find the mean and standard deviation of x bar
We have that [tex]\mu = 75, s = \frac{16}{\sqrt{64}} = 2[/tex].
So the correct answer is:
c) 75, 2
