Answer:
86MJ
Explanation:
THE TOPIC FROM WHICH THE QUESTION IS OBTAINED IS WORK, ENERGY AND POWER
- Power is defined as the time rate of doing work.
- Power =[tex]\frac{Energy used/ work done}{time}[/tex]
- If the energy use is in joules and the time is in seconds, then power is a measure of watts.
1watt = 1 joule per second.
- According to the question, we need to find how much energy does one house use during each 24 hour day ( Already given time = 24hours) when the average rate of electric energy consumption in one house is 1.0 kW ( we have been given power = 1kW).
- Power = 1kW = 1 × 10³W
- Time = 24hours = 24 ×3600 = 86400seconds.
- It is important we have our time in seconds so as to be consistent with unit and dimension
Power = [tex]\frac{Energy used/ work done}{time}[/tex]
1 × 10³W =[tex]\frac{Energy used}{86400}[/tex]
- Energy used =1 × 10³W × 86400
- Energy used = 86400000J = 86.4 × [tex]10^{6}[/tex]W = 86.4MJ
The question requested the answer in 2 significant figures and the answer is 86MJ
