Answer:
The difference between the two population is mean
Explanation:
Let the population mean for Germany and Great Britain be represented by [tex]\mu_1[/tex] and [tex]\mu_2[/tex] respectively hence
Null hypothesis
[tex]H_o: \mu_1-\mu_2=0[/tex]
Alternative hypothesis
[tex]H_1: \mu_1-\mu_2\neq 0[/tex]
Taking [tex]\alpha=0.05[/tex]
[tex]s_d=0.3055[/tex]
[tex]\bar d=\bar x-\bar y=0.0518[/tex]
Sample size, n=145
Student’s t statistics is given by
[tex]t=\frac {\bar d \sqrt n}{s_d}=\frac {0.0518\times \sqrt 145}{0.3055}=2.042[/tex]
From t table, [tex]t_{n-1,\alpha/2}=t_{144,0.025}=1.977[/tex]
The decision rule is to reject null hypothesis if
[tex]\frac {\bar d \sqrt n}{s_d}>t_{n-1, \alpha/2}[/tex]
Therefore, we reject the null hypothesis because the computed t value is more than critical value. We conclude that the difference between the two population is mean.
