Answer:
[tex]d =4.77\times 10^{-5}\ m[/tex]
Explanation:
given
wavelength of light λ = 479 nm
= 479 x 10⁻⁹ m
the angle
θ = 1.15 / 2 = 0.575°
using
condition for diffraction minimum ,
d sinθ = m λ
for first minimum m = 1
d sinθ = λ
therefore ,
slit width
[tex]d =\dfrac{\lambda}{sin\theta}[/tex]
[tex]d =\dfrac{479\times 10^{-9}}{sin 0.575^0}[/tex]
[tex]d =\dfrac{479\times 10^{-9}}{0.01}[/tex]
[tex]d =4.77\times 10^{-5}\ m[/tex]
hence, the width of the slit is equal to [tex]d =4.77\times 10^{-5}\ m[/tex]
