Answer:
The dissociation of [tex]H_{3}PO_{4}[/tex] is as follows.
[tex]H_{3}PO_{4} \leftrightarrow H^{+}(aq)+H_{2}PO_{4}^{-}[/tex]
Explanation:
Molecular equation:
In a molecular equation, reactants are present in the molecular form rather than ionic form.
[tex]NaHSO_{3}(aq)+H_{2}O(l)\leftrightarrow H_{2}SO_{3}(aq)+NaOH(aq)[/tex]
Complete ionic equation:
An ionic equation shows the complete ions in the solution.
[tex]Na^{+}(aq)+OH^{-}(aq)+H_{2}SO_{3}(aq)\rightleftharpoons Na^{+}(aq)+HSO_{3}^{-}(aq)+H_{2}O(l)[/tex]
Net ionic equation:
A reaction shows only those ions are participating in the reaction.
[tex]HSO_{3}^{-}(aq)+OH^{-}(aq)\rightleftharpoons SO_{3}^{2-}(aq)+H_{2}O(l)[/tex]
The dissociation of [tex]H_{3}PO_{4}[/tex] is as follows.
[tex]H_{3}PO_{4} \leftrightarrow H^{+}(aq)+H_{2}PO_{4}^{-}[/tex].