7. How long does it take a ball rolling down a hill to change its speed from 3 m/sec to 34.5 m/sec
if it accelerates at a rate of 3.5 m/sec ??

Respuesta :

The time elapsed is 9 seconds

Explanation:

The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:

[tex]v=u+at[/tex]

where :

v is the final velocity  of the ball

u is the initial velocity

a is the acceleration

t is the time  elapsed

For the ball in this problem, we have:

u = 3 m/s is the initial velocity

v = 34.5 m/s is the final velocity

[tex]a=3.5m/s^2[/tex] is the acceleration

Solving for t, we find the time taken for this change in velocity:

[tex]t=\frac{v-u}{a}=\frac{34.5-3}{3.5}=9 s[/tex]

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