Based on the heat of vaporization of water, the mass of water left after 700 kJ of heat is added to 700 g of water at 70 degrees C is 429 g.
What mass of water is evaporated?
To determine the mass of water evaporated, we first determine the heat required to raise water at 70° C to water at 100°C.
Heat required = mass * specific heat capacity of water * temperature change.
Heat required = 700 * 4.18 * 30
Heat required = 87780 J
Heat left to evaporate water = 700000 J - 87780 = 612220 J
Heat required to vaporize water = mass x latent heat of vaporization of water
Mass of water vaporized = Heat/ latent heat of vaporization of water
Mass of water vaporized = 612220 J/ 22.6*10^5 J/kg.
Mass of water vaporized = 0.271 kg = 271 g
Mass of water left = 700 - 271 g
Mass of water left = 429 g
Therefore, the mass of water left after 700 kJ of heat is added to 700 g of water at 70 degrees C is 429 g.
Learn more about heat of vaporization at: https://brainly.com/question/486624
