Which is the graph of the linear inequality y < 3x + 1? On a coordinate plane, a solid straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the left of the line is shaded. On a coordinate plane, a solid straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the right of the line is shaded. On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the left of the line is shaded. On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1). Everything to the right of the line is shaded.

The statement which represents the graph of the inequality y<3x + 1 is - 'On a coordinate plane, a dashed straight line has a positive slope and goes through (- 1, - 2) and (0, 1). Everything to the right of the line is shaded.'

What is inequality?

"It is a mathematical statement which there is an an order relationship (greater than, greater than or equal to, less than, or less than or equal to) between two algebraic expressions."

For given question,

We have been an inequality y < 3x + 1

We need to find the correct statement that describes the graph of the given inequality.

The graph of inequality y < 3x + 1 is as shown in following figure.

We can observe that, the graph of inequality y < 3x + 1 is a dashed straight line has a positive slope and goes through (negative 1, negative 2) and (0, 1).

Also, the region on the right of the line is shaded.

Therefore, the statement which represents the graph of the inequality y<3x + 1 is - 'On a coordinate plane, a dashed straight line has a positive slope and goes through (- 1, - 2) and (0, 1). Everything to the right of the line is shaded.'

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