Respuesta :
Answer:
The mid point of segment connecting (-1, -9) and (-10, 4) is [tex](\frac{-11}{2} , \frac{-5}{2})[/tex]
Step-by-step explanation:
The coordinates of the given points are A(-1,-9) and B (-10,4).
Here, let us assume the point P (x,y) is the mid point of the segment AB.
By MID POINT FORMULA:
The mid point of segments with points ( x1,y1) and (x2,y2) is given as:
[tex](x,y) = (\frac{x_1 +x_2}{2} , \frac{y_1 +y_2}{2})[/tex]
So, here the coordinates of P are : [tex](x,y) = (\frac{-1 + (-10)}{2} , \frac{-9+ 4}{2}) = (\frac{-11}{2} , \frac{-5}{2})[/tex]
⇒[tex]P(x,y) = (\frac{-11}{2} , \frac{-5}{2})[/tex]
Hence, the mid point of segment connecting (-1, -9) and (-10, 4) is [tex](\frac{-11}{2} , \frac{-5}{2})[/tex]
