Respuesta :
Answer:
Original dimension =[tex] 0.127 \times 0.09525 [/tex] inches.
Step-by-step explanation:
Marie has a copy of the painiting whose dimensions = 2 \times 1.5 inches
Scale of the copy is 1 inch equivalent to 40 centimeters.
Originally, 1 inch is equivalent to 2.54 centimeters.
Thinking logically , we see that in Marie's copy , the painting is enlarged.
In place of 2.54 cm , the scale was taken to be 40 cm.So to find the equivalence factor of the original painting ,we need to divide 2.54 by 40.
The equivalence factor of original painting = [tex]\frac{2.54}{40}[/tex]
= 0.0635
Hence the original dimensions =[tex]initial dimension \times equivalence factor[/tex]
=[tex] (2 \times 1.5) \times 0.0635 [/tex]
=[tex] 0.127 \times 0.09525[/tex] inches.
