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Air at 80oF is to flow through a 2-ft pipe at an average velocity of 6 ft/s. What size pipe should be used to move water at 60oF and average velocity of 3.5 ft/s if Reynolds number similarity is enforced?

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Khoso123

Answer:

D=0.245 ft

Explanation:

Reynolds number for air

Rₐ(air)=Rₐ(water)

[tex]\frac{pVD}{u}=\frac{pVD}{u}[/tex]

Simplify it we get

[tex]\frac{VD}{v}=\frac{VD}{v}\\\frac{6*2}{1.69*10^{-4} }=\frac{3.5D}{1.21*10^{-5} }\\[/tex]

D=71005.95/289256

D=0.245ft

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