An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 581 km from the center of asteroid Y, along the straight line joining the centers of the asteroids. What is the ratio of the masses X/Y of the asteroids? Show all work and circle answe

Respuesta :

Answer:

0.05806

Explanation:

[tex]m_x[/tex] = Mass of asteroid x

[tex]m_y[/tex] = Mass of asteroid y

[tex]r_x[/tex] = Distance from asteroid x = 140 km

[tex]r_y[/tex] = Distance from asteroid y = 581 km

m = Mass of asteroid

Force of gravity between asteroid x and the astronaut

[tex]F_1=\frac{Gm_xm}{r_x^2}\\\Rightarrow F_1=\frac{Gm_xm}{140^2}[/tex]

Force of gravity between asteroid x and the astronaut

[tex]F_2=\frac{Gm_ym}{r_y^2}\\\Rightarrow F_2=\frac{Gm_ym}{581^2}[/tex]

Here these two forces are equal as they are in equilibrium

[tex]\frac{Gm_xm}{140^2}=\frac{Gm_ym}{581^2}\\\Rightarrow \frac{m_x}{140^2}=\frac{m_y}{581^2}\\\Rightarrow \frac{m_x}{m_y}=\frac{140^2}{581^2}\\\Rightarrow \frac{m_x}{m_y}=0.05806[/tex]

The ratio of the masses of the asteroid is 0.05806