Answer:
x(spring stretch)=1.74×10⁻³ meter
Explanation:
Given Data
l (length)=0.175 m
v (speed)= 3.86 m/s
x₁(stretch)=0.0140 m
x(spring stretch)=?
Solution
Centripetal force=Spring Constant
[tex]\frac{mv^{2} }{l}=kx_{1}\\ k=(1/x_{1} )\frac{mv^{2} }{l}\\ k=(1/0.014)(\frac{m(3.86)^{2} }{(0.175+0.014)} )\\k=m*5630.99[/tex]
as
Spring force = gravitational force
[tex]kx=mg\\x=\frac{mg}{k}\\ x=\frac{m(9.8)}{m*5630.99}\\ x=\frac{9.8}{5630.99}\\ x=1.74*10^{-3} meter[/tex]
