Answer:
t = 23,4 min
Explanation:
The integrated rate law for a reaction of the form A + B → Products is:
[tex]ln\frac{[B][A]_0}{[B]_{0}[A]} = k ([B]_{0} - [A]_0)t[/tex] (1)
For the reaction:
CH₃CH₂NO₂ + OH⁻ → H₂O + CH₃CHNO₂
The [A]₀ is [CH₃CH₂NO₂]₀ = 0,005M and [B]₀ = [OH⁻]₀ = 0,006M
90% of [A]₀ is 0,005M×0,9 = 0,0045M consumed
That means [A] = 0,005M - 0,0045M = 0,0005M
And [B] = 0,006M - 0,0045M = 0,0015M
Replacing in (1) knowing k = 39,1min⁻¹mol⁻¹:
[tex]ln\frac{[0,0015M][0,005M]}{[0,006M][0,0005M]} = k ([0,006M] - [0,005M])t[/tex]
ln 2,5 = (39,1min⁻¹mol⁻¹× 0,001M) t
t = 23,4 min
I hope it helps!
