Answer: she would be having $64 on the sixth day
Step-by-step explanation:
Each day,she doubles the number of dollars she saved on the previous day. This amount of money that she saves each day is increasing in a geometric progression. The formula for the nth term of a geometric progression is
Tn = ar^(n - 1)
Where
a is the first term of the sequence
r is the common ratio
n is the number of terms
To determine how much she saves on the sixth day,
n = 6
a = 2
r = 2
T6 = 2×2^(6 - 1)
T6 = 2 × 2^5
T6 = 64
