Answer:
The ball will reach an height of 31.88 meters before coming to a stop.
Explanation:
we know that by equation of motion [tex]v^{2} = u^{2} + 2as[/tex]
where v is the final velocity of the ball , u is the initial velocity of the ball , a is acceleration due to gravity and s is the distance traveled by the ball.
a = -9.8 [tex]\frac{m}{s^{2}}[/tex]
and u = 25 m/s
and v = 0
therefore s = [tex]\frac{u^{2}}{2a}[/tex]
so s = 31.88 meters
