Answer:
0.0606
Step-by-step explanation:
Given that test statistic for a left tailed test is
z=-1.55
[tex]H_0: \bar x=\mu\\H_a: \bar x < \mu[/tex]
Significance level = 0.10
let us find p value from z value
p value for left tailed is
0.060571
Since p value < 0.10 our alpha, we reject null hypothesis.
p value = 0.0606
Conclusion: Reject null hypothesis.
There is statistical evidence to show that sample mean is less than population mean.