Answer:
Option B can be quadratic.
Step-by-step explanation:
Take a look at the data.
A quadratic equation is of the form ,
[tex]y = ax^{2} +bx + c[/tex],
where, a,b,c are constants.
To find an unknown equation of 3 variables,
we need 3 points lying on the equation.
here they have given, 5 points, meaning all should lie on the curve.
For first option, inserting first 3 points to find equation, we get equation as,
[tex]y = x^{2} -4x +11[/tex], but the rest points don't satisfy the curve.
So first option is not quadratic.
Similarly, it can be shown that option C and D are also not quadratic.
While, in option B, it is clear that for every y, x is y squared,
[tex]x = y^{2}[/tex], thus quadratic in nature.
