Respuesta :
Answer:
battery life in year = 9 years and 48 days
Explanation:
given data
Battery Ampere-hours = 1.5
Pulse voltage = 2 V
Pulse width = 1.5 m sec
Pulse time period = 1 sec
Electrode heart resistance = 150 Ω
Current drain on the battery = 1.25 µA
to find out
battery life in years
solution
we get first here duty cycle that is express as
duty cycle = [tex]\frac{width}{period}[/tex] ...............1
duty cycle = 1.5 × [tex]10^{-3}[/tex]
and applied voltage will be
applied voltage = duty energy × voltage ...........2
applied voltage = 1.5 × [tex]10^{-3}[/tex] × 2
applied voltage = 3 mV
so current will be
current = [tex]\frac{applied\ voltage}{resistance}[/tex] ................3
current = [tex]\frac{3}{150}[/tex]
current = 20 µA
so net current will be
net current = 20 - 1.25
net current = 18.75 µA
so battery life will be
battery life = [tex]\frac{1.5}{18.75*10^{-6}}[/tex]
battery life = 80000 hours
battery life in year = [tex]\frac{80000}{8760}[/tex]
battery life in year = 9.13 years
battery life in year = 9 years and 48 days
