Answer:
(-6, 9) is the solution set for given system.
Step-by-step explanation:
Given that:
3x-y=-27 ----------- eq1
4x+2y=-6 --------- eq2
Solving by combining the equations:
Dividing eq2 by 2 we get:
2x + y = -3 ------- eq3
Now add eq1 and eq3, we get:
5x = -30 (y from both equations will be cancelled out)
Dividing both sides by 5:
x = -6
Now putting value of x back in eq3:
2(-6) + y = -3
-12 + y = -3
Adding 12 on both sides:
y = -3 + 12
y = 9
So the solution set for given system is (-6, 9)
i hope it will help you!
