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If the rate of decrease for the partial pressure of N2H4 in a closed reaction vessel is 80 torr/h , what is the rate of change for the partial pressure of NH3 in the same vessel?

Respuesta :

igeclement43

Answer:Pressure of NH3 increases at the rate of 160torr/hr

Explanation:

According to the equation below

N2H4 (g) + H2 (g) ==> 2 NH3 (g)

It shows that 1mol of N2H4 will gives 2mol of NH3

Therefore, if the partial pressure rate of N2H4 is 80torr/hr, the partial pressure of NH3 increases by 2×80=160torr/hr

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