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A reaction has a rate constant of 0.00871 sec-1, how much of the compound (in mol/L) is left after 1.66 sec, if there was 0.903 mol/L at the start? (give answer to 3 decimal places)?

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Answer

Consider the following calculations

Explanation:

first order reaction

k = (1/t)ln(a/x)

rate constant k = 0.0592 sec-1.

t = time = 0.865 min = 51.9 sec

a= initial concentration = 0.125 mol/L

x = after t sec concentration = ?

0.0592 = (1/51.9)ln(0.125/x)

x = 0.0058 mol/L

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