Answer:
the maximum velocity is approximately 36.878 m/s
Explanation:
We can apply a balance of mechanical energy.
P1 + ρgy1 + 1/2ρv1² = P2 + ρgy1 + 1/2ρv2² + Fr
where P=pressure , ρgy = hydrostatic pressure , 1/2ρv² = dynamic pressure , Fr= friction
we can neglect the variations of height in the nozzle and depreciate the low velocity term, therefore
P1 - P2 - Fr= 1/2ρv2²
the maximum velocity is found in case of no friction , then
P1 - P2 = 1/2 ρ vmax²
therefore
vmax =√2(P1-P2)/ ρ
assuming the density of water as ρ= 1000 kg/m³
vmax =√2(P1-P2)/ ρ = √(2*(780000 Pa - 100000 Pa)/1000 Kg/m³ ) = 36.878 m/s
