The change in velocity is 10 mi/h (4.47 m/s)
Explanation:
The change in velocity of the motorcyclist is given by
[tex]\Delta v = v-u[/tex]
where
v is the final velocity
u is the initial velocity
In this problem, we have
u = 0 (the motorbike starts from rest)
v = 10 mi/h
Therefore, the change in velocity is
[tex]\Delta v = 10 -0 = 10 mi/h[/tex]
And keeping in mind that
1 mile = 1609 m
1 h = 3600 s
We can convert it into m/s:
[tex]\Delta v = 10 \frac{mi}{h} \cdot \frac{1609 m/mi}{3600 s/h}=4.47 m/s[/tex]
Learn more about velocity:
brainly.com/question/5248528
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