Answer:
Young modulus, [tex]Y=2\times 10^{11}\ N/m^2[/tex]
Explanation:
Given that,
Length of the metal rod, l = 4 m
Area of cross section of the metal rod, [tex]A=0.5\ cm^2[/tex]
Change in length, [tex]\Delta l=0.2\ cm[/tex]
Tension, T = 5000 N
To find :
The Young modulus of this metal
Solution,
The formula for the Young modulus of the metal is given by :
[tex]Y=\dfrac{Fl}{A\Delta l}[/tex]
[tex]Y=\dfrac{5000\times 4}{0.5\times 10^{-4}\times 0.2\times 10^{-2}}[/tex]
[tex]Y=2\times 10^{11}\ N/m^2[/tex]
So, the Young modulus of this metal is [tex]2\times 10^{11}\ N/m^2[/tex]
